[语音合成] c语言实例 100例题

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发表于 2022-9-28 16:00:04
适关于初学者有问题和解题方法如【程序1】标题:有1、2、3、4个数字,能构成多少个互不一样且无重复数字的三位数?都是多少?1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。构成一切的摆放后再去掉不满足条件的摆放。2.程序源代码:main(){inti,j,k;printf(\n);for(i=1;ilt;5;i++)/
以下为三重循环
/for(j=1;jlt;5;j++)for(k=1;klt;5;k++){if(i!=ki!=jj!=k)/
保证i、j、k三位互不一样
/printf(%d,%d,%d\n,i,j,k);}}
C言语实例100例\C言语实例1-10.txt
C言语实例100例\C言语实例11-20.txt
C言语实例100例\C言语实例21-30.txt
C言语实例100例\C言语实例31-40.txt
C言语实例100例\C言语实例41-50.txt
C言语实例100例\C言语实例51-60.txt
C言语实例100例\C言语实例61-70.txt
C言语实例100例\C言语实例71-80.txt
C言语实例100例\C言语实例81-90.txt
C言语实例100例\C言语实例91-100.txt
.....

(It is suitable for beginners to have questions and problem-solving methods such as [Program 1] Title: With 1, 2, 3, and 4 numbers, how many three-digit numbers can be formed that are different from each other and have no repeating numbers? How many? 1. Program analysis: The numbers that can be filled in the hundreds, tens, and ones are 1, 2, 3, and 4. After the placement that constitutes everything, the placement that does not meet the conditions is removed. 2. Program source code: main(){inti,j,k;printf(\n);for(i=1;ilt;5;i  )/
The following is a triple loop
/for(j=1;jlt;5;j  )for(k=1;klt;5;k  ){if(i!=ki!=jj!=k)/
Make sure that i, j, and k are different from each other
/printf(


n,i,j,k);}}
100 examples of C language examples\C language examples 1-10.txt
100 C language examples\C language examples 11-20.txt
100 C language examples\C language examples 21-30.txt
100 C language examples\C language examples 31-40.txt
100 C language examples\C language examples 41-50.txt
100 C language examples\C language examples 51-60.txt
100 C language examples\C language examples 61-70.txt
100 C language examples\C language examples 71-80.txt
100 C language examples\C language examples 81-90.txt
100 C language examples\C language examples 91-100.txt
.....)

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