c,c++,java笔试题大全

1.求下面函数的返回值(微软)intfunc(x){intcountx=0;while(x){countx++;x=x(x-1);}returncountx;}假定x=9999。答案:8思路:将x转化为2进制,看富含的1的个数。2.啥是“引证”?声明和使用“引证”要注意哪些问题?答:引证即是某个方案变量的“别号”(alias),对使用的操作与对变量直接操作作用完全相同。声明一个引证的时候,牢记要对其进行初始化。引证声明结束后,相当于方案变量名有两个称号,即该方案原称号和引证名,不能再把该引证名作为别的变量名的别号。声明一个引证,不是新定义了一个变量,它只表明该引证名是方案变量名的一个别号,它自身不是一种数据类型,因而引证自身不占存储单元,系统也不给引证分配存储单元。不能建立数组的引证。3.将“引证”作为函数参数有哪些特点?(1)传递引证给函数与传递指针的作用是相同的。这时,被调函数的形参就变成本来主调函数中的实参变量或方案的一个别号来使用,所以在被调函数中对形参变量的操作即是对其相应的方案方案(在主调函数中)的操作。.......
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(1. Find the return value of the following function (Microsoft) intfunc(x){intcountx=0;while(x){countx  ;x=x(x-1);}returncountx;} Assume x=9999. Answer: 8 Ideas: Convert x to binary and see the number of rich 1s. 2. What is a "citation"? What should be paid attention to when declaring and using a "citation"? Answer: A reference is the "alias" of a program variable, and the operation of using it is exactly the same as the direct operation of the variable. When declaring a reference, remember to initialize it. After the citation statement is over, the program variable name has two titles, namely the program's original title and the citation name. The citation name can no longer be used as an alias for other variable names. Declaring a citation does not define a new variable, it only indicates that the citation name is an alias of the program variable name, and it is not a data type itself, so the citation itself does not occupy a storage unit, and the system does not allocate a storage unit to the citation. . Cannot create a reference to an array. 3. What are the characteristics of using "reference" as a function parameter? (1) The function of passing a reference to a function is the same as passing a pointer. At this time, the formal parameter of the called function becomes an alias of the actual parameter variable or scheme in the original calling function, so the operation of the formal parameter variable in the called function is the corresponding scheme scheme. The operation (in the calling function). ......
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